bod5calculationexample

TodeterminetheBOD5ofawastewatersample10,50,75and100mlsamplesofthewastewaterweredilutedto500mlandincubatedat20∘CinBODbottles ...,2022年7月3日—Theresultswereasfollows:WastewaterVolume(mL)51050.InitialDO(mg/L)9.29.18.4.DOafter5days(mg/L)6.94.40.Basedonthedata, ...,,DetermineultimateBODforawastewaterhaving5dayBODat20oCas160mg/L.Assumereactionrateconstantas0.2perday(base10).Solution.BOD5=Lo(1– ...,...

參考資訊如下
To determine the BOD5 of a waste water sample 10, 50, 75 ...

To determine the BOD5 of a waste water sample 10, 50, 75 and 100 ml samples of the waste water were diluted to 500 ml and incubated at 20∘C in BOD bottles ...

To determine the BOD5 of a waste water sample 5, 10 ...

2022年7月3日 — The results were as follows: Wastewater Volume (mL) 5 10 50. Initial DO (mg/L) 9.2 9.1 8.4. DO after 5 days (mg/L) 6.9 4.4 0. Based on the data, ...

BOD Calculation step by step (Biochemical Oxygen Demand)

11.3.2 BOD Model It is generally assumed that the rate at ...

Determine ultimate BOD for a wastewater having 5 day BOD at 20oC as 160 mg/L. Assume reaction rate constant as 0.2 per day (base 10). Solution. BOD5 = Lo ( 1 – ...

A wastewater sample was tested and found to

... Calculate Initial DO in Wastewater*** The initial DO in the wastewater is the BOD of the sample minus the BOD5 given, adjusted for the dilution. $$Initial ...

The BOD 5 of a wastewater sample is 200 mglitre at 20° C. ...

2020年9月3日 — The BOD 5 of a wastewater sample is 200 mg/litre at 20° C. The value of the reaction constant is K = 0.2 day -1 with base 'e'.

In BOD 5 determination of sewage, the initial dissolved ...

2019年8月16日 — Initial DO = 8.3 mg/L Final DO = 2.3 mg/L Dilution Factor = 1/60 The dilution factor 1:60 means 1 ml of sewage is diluted with 60 ml of ...

Calibration steps of BOD5 tester

2023年3月13日 — The BOD5 value is calculated by comparing the dissolved oxygen content of the original water sample and the dissolved oxygen content after 5 ...

Chapter 5

Calculation. 7. Calculate the amount of 1 N sodium hydroxide or 1 N sulfuric acid needed to neutralize the sample to pH 7.0 using the following ...